Question #210c2

1 Answer
Feb 21, 2018

my comp

For resistance between points #F and H#, refer to figure above.
There are three branches connected in parallel.

  1. Series combination of resistors #1and2=2R#
  2. Resistor #3=R#
  3. Series combination of resistors #4and5=2R#

Using the parallel combination formula

#1/R_(eff)=1/(2R)+1/R+1/(2R)#
#=>1/R_(eff)=1/R((1+2+1)/2)#
#=>1/R_(eff)=2/R#
#=>R_(eff)=R/2=6.83/2=3.42\ Omega#

my comp

For resistance between points #F and G#, refer to figure above.
There are four branches connected as shown in each step.

  1. Series combination of resistors #1and2=2R#
  2. Above in parallel with Resistor #3=R#
    Let this be #R_1#
    We have #1/R_1=1/(2R)+1/R#
    #=>1/R_1=1/R(1/2+1)#
    #=>1/R_1=3/(2R)#
    #=>R_1=(2R)/3#
  3. Series combination of resistors #R_1and5=(2R)/3+R=(5R)/3#
  4. Parallel combination of above with resistor #4#.
    Using parallel combination formula we get
    #1/R_(eff)=3/(5R)+1/R#
    #=>1/R_(eff)=1/R(3/5+1)#
    #=>1/R_(eff)=8/(5R)#
    #=>R_(eff)=(5R)/8=(5xx6.83)/8=4.27\ Omega#