Question

Question #f1328

Answer 1

`0.1ms^-1`

Explanation:

The mass of the ship given is `3xx10^7kg`

The force applied on the ship is `5xx10^4N`

From this we can find the acceleration of the ship :

  Force = mass x acceleration

acceleration= `"Force"/"mass"`

Hence acceleration 'a' is given by `(5xx10^4)/(3xx10^7)`

a= `5/3xx10^-3` `ms^-2`

since initially the ship is at rest it 's initial velocity is zero and from the question it is given that the ship has moved 3 meters

The relation between the final velocity(velocity of the ship after travelling 3 meters ) and it's acceleration is given by

`v^2=u^2+2xxaxxs`

Here 's' is the displacement and it is 3 meters. ( `u=0` since the initially the ship is at rest)

Let's solve for v(The final velocity)

`v^2=0+2xx5/3xx10^-3xx3`
`v^2=10xx10^-3`
`v=` `sqrt(10^-2)`
`v=10^-1rArr0.1 ms^-1`

Therefore the speed of the ship is `0.1 ms^-1`

NOTE:
In the question it is given that the resistance due to water is negligible and so we doesn't take that into account .If this line is not given we also take the opposing force provided by the water into account.