Question #b6f4c

1 Answer
Sep 12, 2017

Answer:

Approx. #10*mL#

Explanation:

With all these problems, the priority is to write a stoichiometrically balanced equation:

#H_2SO_4(aq) + 2NaOH(aq) rarr Na_2SO_4(aq) + 2H_2O(l)#

And thus ONE equiv of sulfuric acid reacts with TWO equiv of sodium hydroxide.

#"Moles of sodium hydroxide"=60.2*mLxx10^-3*L*mL^-1xx0.427*mol*L^-1=0.0257*mol#.

And thus #(0.0257*mol)/2# #H_2SO_4# are required.....

And so we take the quotient....

#((0.0257*mol)/2)/(1.28*mol*L^-1)xx10^3*mL*L^-1=10.0*mL#

Note that normally, when we do a titration we aim to use a volume of #15-20*mL# in order to minimize errors. Of course, you gots no choice when solving a problem.....