How many gold atoms are there in a 5.37*mol quantity of the metal?

Sep 13, 2017

How many? Well, $5.37 \cdot m o l \times {N}_{A} \ldots . .$

Explanation:

How many? Well, $5.37 \cdot m o l \times {N}_{A} \ldots . .$ where ${N}_{A} = \text{Avogadro's number}$, $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.

And so we takes the product....

$5.37 \cdot m o l \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1 = 3.23 \times {10}^{24}$ individual gold atoms; pretty vast but not infinite.

The current price of gold is $1,323.86*USD*oz^-1. Given that $1 \cdot o z \equiv 28.3 \cdot g\$, how much is this molar quantity of gold worth?