How many atoms in a mass of ONE MOLE of #"magnesium nitrate"#?

1 Answer
anor277
Sep 15, 2017

You have the formula #Mg(NO_3)_2#....

Explanation:

And so there are #1xxMg+2xxN+6xxO*"atoms"#.......

And we could calculate the molar mass of the nitrate....

...which is #148.30*g*mol^-1#. And thus in #"Avogadro's number of magnesium nitrate formula units,"# #"i.e. a mass of 148.3 g"#, #N_A-=6.022xx10^23*mol^-1#, there are #1xxN_A(Mg) + 2xxN_A(N) + 6xxN_A(O)-=9N_A# atoms in toto....

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