How many atoms in a mass of ONE MOLE of $magnesium nitrate$ $"magnesium nitrate"$ ?

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How many atoms in a mass of ONE MOLE of $magnesium nitrate$ $"magnesium nitrate"$ ?

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Answer 1 · 2017-09-15T18:46:14

You have the formula $M {g (N O_{3})}_{2}$ $Mg(NO_3)_2$ ....

Explanation:

And so there are $1 \times M g + 2 \times N + 6 \times O \cdot atoms$ $1xxMg+2xxN+6xxO*"atoms"$ .......

And we could calculate the molar mass of the nitrate....

...which is $148.30 \cdot g \cdot m o l^{- 1}$ $148.30*g*mol^-1$ . And thus in $Avogadro's number of magnesium nitrate formula units,$ $"Avogadro's number of magnesium nitrate formula units,"$ $i.e. a mass of 148.3 g$ $"i.e. a mass of 148.3 g"$ , $N_{A} \equiv 6.022 \times 10^{23} \cdot m o l^{- 1}$ $N_A-=6.022xx10^23*mol^-1$ , there are $1 \times N_{A} (M g) + 2 \times N_{A} (N) + 6 \times N_{A} (O) \equiv 9 N_{A}$ $1xxN_A(Mg) + 2xxN_A(N) + 6xxN_A(O)-=9N_A$ atoms in toto....

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How many atoms in a mass of ONE MOLE of $magnesium nitrate$ $"magnesium nitrate"$ ?

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How many atoms in a mass of ONE MOLE of "magnesium nitrate"magnesium nitrate"magnesium nitrate"?

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How many atoms in a mass of ONE MOLE of $magnesium nitrate$ $"magnesium nitrate"$ ?