Question #91a5e

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Answer 1 · 2017-09-20T14:25:08

#lambda=250m#

The product of frequency and wavelength will be equal to the velocity of light c.

#c=fxxlamda#

#lambda=c/f#

where

#lamda# is the wavelength of the wave,
#f# is the frequency of the wave,
#c# is the velocity of light which is equal to #3xx10^8ms^-1#

#f=1200kHZ=1200xx10^3HZ#

Substituting the values,

#lambda=(3xx10^8)/(1200xx10^3)m#
#lambda=250m#
Hence the wavelength of the given wave is #250m#