Let #x# be the smallest integer of the three. Since odd integers are two numbers away from the previous one, the other two integers can be represented as #x+2# and #x+4#.
Now, if the three integers add up to #-219#, we can create an equation (the sum of the three soon-to-be-solved integers):
#x+(x+2)+(x+4) = -219#
Then, combine like terms and solve.
#x+x+2+x+4 = -219#
#3x+2+4 = -219#
#3x+6 = -219#
#3x = -225#
#x = -75#
Now we know that the smallest integer of the three odd integers is #-75#. Now we can add #2# and #4# to #-75# to get our two other integers.
#-75+2 = -73#
#-75+4 = -71#
The three consecutive odd integers that add to #-219# are #-75,-73,-71#