# Question #2fdbe

Sep 22, 2017

Add $N {H}_{\text{3}}$ under alcoholic conditions.

#### Explanation:

The molecular formula for Ethyl Chloride is $C {H}_{\text{3"CH_"2}} C l$

To convert a haloalkane to a amine you add $N {H}_{\text{3}}$ under alcoholic conditions.

So in this reaction $N {H}_{\text{2}}$ is substituted for the halogen ($C l$), as the Chlorine is removed it reacts with the Hydrogen that was lost from the $N {H}_{\text{3}}$, this results in a $H C l$ being produced.

The resulting reaction is:

$C {H}_{\text{3"CH_"2"Cl + NH_"3" -> CH_"3"CH_"2"NH_"2}} + H C l$