What is lim_(x->0) sin(sin3x)/(sin 7x) ?
1 Answer
Sep 22, 2017
Explanation:
My first impression is that:
lim_(x->0) sin(sin3x)/(sin 7x) = 3/7
since
Let us start by assuming:
lim_(t->0) sin t / t = 1
Then:
lim_(x->0) sin(sin3x)/(sin7x)
= lim_(x->0) (sin(sin3x)/(sin3x) * (sin3x)/(3x) * (7x)/(sin 7x)) * 3/7
= 1 * 1 * 1 * 3/7
= 3/7