Question

Question #a790e

Answer 1

The ball will fall 0.757 m while traveling from the pitcher to the catcher if thrown at 43.3 m/s.

Explanation:

What is the time to reach the catcher?
speed = distance/time so
time = distance/speed

`t = s/v = (17.0 cancel(m)) / (43.3 (cancel(m)/s)) = 0.393 s`

How far vertically would a ball fall, if just dropped, in 0.393 s?
`s = u*t + (1/2)*a*t^2`
`s = u*t + (1/2)*g*t^2`
`s = 0*0.393 s + (1/2)*9.8 m/s^2*(0.393 s)^2 = 0.757 m`

The ball would also fall 0.757 m while traveling from the pitcher to the catcher if thrown at 43.3 m/s. If thrown at a speed in excess of 43.3 m/s, it will fall less distance.

I hope this helps,
Steve