Question

Question #16a73

Answer 1

...I'm going to interpret the function as

`y = (cos(x))^3`

...so the derivative in this case can be found via the chain rule:

if `y = u(v(x))` then `(dy)/dx = (du)/(dv) (dv)/dx`

and in this case `u(v) = v^3`, and `v(x) = cos(x)`

so `(du)/(dv) = 3v^2 = 3(cos(x)^2)`, and `(dv)/dx = -sin(x)`

put these all together:

`(dy)/dx = (3cos^2x)(-sinx)`

GOOD LUCK!