Yes, the mole ratio that exists between iron and iron(III) oxide can be written as
The idea here is that the mole ratio that exists between two chemical species that take part in a reaction is given by the coefficients added in the balanced chemical equation.
In your case, you have
#color(blue)(4)"Fe"_ ((s)) + 3"O"_ (2(g)) -> color(red)(2)"Fe"_ 2"O"_ (3(s))#
According to the balanced chemical equation, you have a
This tells you that for every
So you can say that iron and iron(III) oxide have a
You can divide both values by
#(color(blue)(4)color(white)(.)"moles Fe")/(color(red)(2)color(white)(.)"moles Fe"_ 2"O"_ 3) = "2 moles Fe"/("1 mole Fe"_ 2 "O"_ 3)#
You can thus say that when elemental iron reacts with enough oxygen gas, the reaction consumes twice as many moles of iron as the number of moles of iron(III) oxide it produces.