If #10*g# of calcium carbonate is heated to decomposition, what volume of #CO_2(g)# will result at #"STP"#?

1 Answer
anor277
Oct 4, 2017

A bit over #2*L#...

Explanation:

I assume you assess the ENDOTHERMIC reaction.....

#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)uarr#

Now the molar quantity of #"calcium carbonate"# is...

#(10*g)/(100.09*g*mol^-1)=0.0999*mol#.

And given fierce heating we should generate equimolar carbon dioxide. And thus a volume at #"STP"=0.0999*molxx22.4*L*mol^-1=??*L#

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