# Question #231c3

##### 1 Answer

Here's what I got.

#### Explanation:

The idea here is that a solution's **percent concentration by mass**, **for every**

In your case, the **for every** **of solution**.

So, if

#25 color(red)(cancel(color(black)("g AgNO"_3))) * overbrace((color(blue)("100 g")color(white)(.)"solution")/(10color(red)(cancel(color(black)("g AgNO"_3)))))^(color(black)("= 10"color(blue)(%) color(white)(.)"by mass AgNO"_3)) = color(darkgreen)(ul(color(black)("250 g solution")))#

I'll leave the answer rounded to two **sig figs**, but keep in mind that you have one significant figure for the solution's percent concentration.

So the correct answer should be rounded to *one significant figure*

#"mass of solution = 300 g"#