# Question 231c3

Oct 7, 2017

Here's what I got.

#### Explanation:

The idea here is that a solution's percent concentration by mass, $\text{m/m%}$, tells you the number of grams of solute present for every $\text{100 g}$ of the solution.

In your case, the 10color(blue)(%)# by mass silver nitrate solution will contain $\text{10 g}$ of silver nitrate, the solute, for every $\textcolor{b l u e}{\text{100 g}}$ of solution.

So, if $\textcolor{b l u e}{\text{100 g}}$ of solution contain $\text{10 g}$ of silver nitrate, it follows that $\text{25 g}$ of silver nitrate would be present in

$25 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{g AgNO"_3))) * overbrace((color(blue)("100 g")color(white)(.)"solution")/(10color(red)(cancel(color(black)("g AgNO"_3)))))^(color(black)("= 10"color(blue)(%) color(white)(.)"by mass AgNO"_3)) = color(darkgreen)(ul(color(black)("250 g solution}}}}$

I'll leave the answer rounded to two sig figs, but keep in mind that you have one significant figure for the solution's percent concentration.

So the correct answer should be rounded to one significant figure

$\text{mass of solution = 300 g}$