Question #31ec4
3 Answers
Explanation:
As we increase the value of
In fact, as you take any polynomial to infinity, the only term that will matter is the one with the biggest degree, since it will dominate all of the others as far as rate of growth.
Therefore, we can say that:
#lim_(x->oo)(2x^2 - 1/4x^3 - 5x - 1)#
#= lim_(x->oo)(cancel(2x^2) - 1/4x^3 - cancel(5x) - cancel(1))#
#= lim_(x->oo)(-1/4x^3)#
And as we plug bigger and bigger values of
Final Answer
Explanation:
#"divide terms on numerator/denominator by the "#
#"highest power of x that is "x^3#
#rArr((2x^2)/x^3-1/x^3)/((4x^3)/x^3-(5x)/x^3-1/x^3)=(2/x-1/x^3)/(4-5/x^2-1/x^3)#
#rArrlim_(xtooo)(2x^2-1)/(4x^3-5x-1)#
#=lim_(xtooo)(2/x-1/x^3)/(4-5/x^2-1/x^3)#
#=0/(4-0-0)=0#
Explanation:
For
Since
Dividing by