How much heat in kcal does "26.4 g" of diethyl ether absorb if it was heated from 12.7^@ "C" to 30.5^@ "C"? The specific heat capacity is "0.895 cal/g"^@ "C" in this temperature range.
1 Answer
Oct 12, 2017
q = "0.421 kcal"
Explanation:
q=mC_P∆T
Here,
m="26.4 g" , the mass of diethyl etherC_P= "0.895 cal"/("g"cdot^@"C") , its specific heat capacity∆T=30.5^@ "C" - 12.7^@ "C" = 17.8^@ "C" , its change in temperatureq=? , its heat flow
So,
q=26.4cancel(g) times 0.895"cal"/cancel(g^@C)times17.8^@cancelC
q="420.6 cal" = ul("0.421 kcal")