Question #efa64

1 Answer
Manikandan S.
Oct 10, 2017

67.2 L

Explanation:

You have 96 g of #O_2#.
1 mol of #O_2# = 32 g
96 g of #O_2# = 96/32 mol of #O_2#
#=3 # mol of #O_2#

1 mol of gas occupies 22.4L at STP
3 mol of #O_2# occupies #3\times22.4# L at STP

The volume occupied by 96 g of #O_2# at STP = 67.2 L

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