Question

Question #f479f

Answer 1

0.61 moles of `O_2` and 1.22 moles of `H_2`O

Explanation:

After balancing the equation we discover that
`O_2` + 2`H_2` `rarr` 2`H_2`O
in other words 1 mole of `O_2` reacts with 2 moles of `H_2` to produce 2 moles of `H_2`O. The ratio of oxygen to hydrogen molecules in the reaction is a 1 : 2 ratio. So we must divide the moles of `H_2` in half to determine the moles of `O_2`. The ratio of `H_2` to `H_2`O is 2 : 2. This reduces to a 1 : 1 ratio, therefore the moles of `H_2` is equal to the moles of `H_2`O produced.