# Question #c6f62

Oct 16, 2017

$- 2 < r \le 0$

#### Explanation:

Split up the inequalities into two parts.
$9 + 7 r > r - 3$ and $r - 3 \ge 7 r + 3$
Solve them.

$9 + 7 r > r - 3$
$6 r > - 12$
$r > - 2$

$r - 3 \ge 7 r + 3$
$0 \ge 6 r$
$0 \ge r$

Since $r$ has to be more than $- 2$ and less than $0$, we can rewrite the inequality as $- 2 < r \le 0$