Question #22513

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Question #22513

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Answer 1 · 2017-10-16T01:07:53

$e^{sin x} (cos x)$ $e^sinx(cosx)$

Explanation:

The derivative of $e^{x}$ $e^x$ is itself.

But since its $x$ $x$ has a function in it we apply the chain rule.
Where we take the derivative of the outside and then multiply it by the derivative of the inside.

Where $e^{sin x}$ $e^sinx$ is our outside and $sin x$ $sinx$ is our inside.

The derivative of $sin x$ $sinx$ is $cos x$ $cosx$

Put them together and you get:

$e^{sin x} (cos x)$ $e^sinx(cosx)$

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Question #22513

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