Question #84c1c
1 Answer
Oct 17, 2017
See the answer below...
Explanation:
When we throw a object on the sky it takes same time to go up as to go downwards...
Hence the object takes#color(red)(3.56/2=1.78s# to rise up or to rise down...
Refer you this for the formulas...
PROBLEM A
Now we have to determine the initial velocity
Hence,
PROBLEM B
#v_f^2=v_i^2+2as# [s=DISPLACEMENT]
#=>v_i^2=2gs#
#=>17.8^2=2xx10xxs#
#=>s=15.842m# Hope the answer helps...
Thank you...