Question #fd5c5

$\sin \left({16}^{\circ}\right)$
The cofunction identity says that $\cos \left(x\right) = \sin \left({90}^{\circ} - x\right)$.
For the given example, $\cos \left({74}^{\circ}\right) = \sin \left({90}^{\circ} - {74}^{\circ}\right) = \sin \left({16}^{\circ}\right)$