Question #31947

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Answer 1 · 2017-10-23T08:55:30

#x=2#

The equation is #log(3x-5)=log(x-1)#

When the base of the #log# is same then -->

#log(f(x))=log(g(x))#

#cancel(log)(f(x))=cancel(log)(g(x))#

#f(x)=g(x)#

Therefore

#log(3x-5)=log(x-1)#

#cancel(log)(3x-5)=cancel(log)(x-1)#

#3x-5=x-1#

#3x-x=-1+5#

#2x=4#

#x=4/2#

#x=2#