Question

Question #ee286

Answer 1

`53.7cm(1dp)`

Explanation:

area of a sector`=theta/360xxpir^2`

`theta = " the angle subtended at the centre"`

`r="the radius of the circle"`

we have

`30=theta/360xxpixx8^2`

`:.theta=(30xx360)/(64xxpi)=53.7cm(1dp)`

Answer 2

`53.7^@" to 1 dec. place"`

Explanation:

`• " area of sector "="area of circle "xxtheta/(2pi)`

`"where r is the radius and "theta" the angle subtended at the "`
`"centre"`

`rArr30=cancel(64pi)^(32)xxtheta/cancel(2pi)=32theta`

`rArrtheta=30/32=0.9375" radians"`

`rArrtheta=0.9375xx180^@/(pi)~~53.7^@" to 1 dec. place"`