Question #d48ce

1 Answer
Manasvini Nittala
Oct 23, 2017

The coefficient of #x^5# is #4032#

Explanation:

The expansion #(1+2x)^9# is of the form #(1+X)^n#
The general term in the expansion #(1+X)^n# is
#T_(r+1)=C_r(X)^n#
Here #X=2x and n=5#
on substituting we get
#(9!)/(4!.5!)(2x)^5# #rArr126*32# #x^5#
The coefficient of #x^5# is #126*32=4032#
#:.# coefficient of #(x)^5=4032 #

Related questions
Impact of this question
629 views around the world
You can reuse this answer
Creative Commons License