Question

What mass of carbon dioxide would result from the complete combustion of `3.4*mg` of methane?

Answer 1

Approx. `0.010*g`......

Explanation:

WE need a stoichiometric equation to represent the combustion:

`CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(g)`

And thus 1 mole of carbon dioxide results from combustion of each mole of methane.

`"Moles of methane"=(3.4xx10^-3*g)/(16.03*g*mol^-1)=2.12xx10^-4*mol`

And thus we get a mass with respect to carbon dioxide of `2.12xx10^-4*molxx44.01*g*mol^-1=9.3*mg`....take that environment.