Question #995d9

1 Answer
Oct 24, 2017

if in the given equation (x^-3.x)+2=0 belongs to RR i.e. real numbers then the equation has no solution,if the equation belongs to complex numbers CC the solution is (i)/sqrt2

Explanation:

x^-3.x+2=0rArr(x)/x^3+2=0rArr1/x^2+2=0rArr2x^2+1=0rArr2x^2=-1rArrx^2=(-1)/2rArrx=sqrt(-1)/sqrt2rArrx=i/sqrt2_
hence this is how u solve it