Question

Question #7fbf4

Answer 1

Third term = `21 x^10`

Explanation:

`(x@^2+1)^7 = x^14 + 7C1 x^12 + 7C2 x^10 + 7C3 x^8 + 7C4 x^6 + 7C5 x^4 + 7C6 x^2 + 1`

Hence the third term is = `7C2 x^19 = (7*6*x^10)/(1*2) = 21x^10`