# Question #21437

##### 1 Answer

Here's what I got.

#### Explanation:

By definition, a **for every**

Now, when you take

#"27 g sugar"/3 = "9 g sugar"#

in about

#"100 g solution"/3 = "33.33 g solution"#

You then add

#"9 g + 10 g = 19 g"#

and the mass of the solution will be

#"33.33 g + 10 g = 43.33 g"#

In order to find the solution's **percent concentration by mass**, you need to figure out the number of grams of sugar present in exactly

To do that, use the known composition of the solution as a *conversion factor*

#100 color(red)(cancel(color(black)("g solution"))) * "19 g sugar"/(43.33 color(red)(cancel(color(black)("g solution")))) = "43.85 g sugar"#

You can thus say that this solution has

#color(darkgreen)(ul(color(black)("% m/m = 43.85% sugar")))#

I'll leave the answer rounded to four **sig figs** because it comes very close to one of the options given to you, i.e. **(4)**