Question

How do you solve `8/11=4/(y+2)`?

Answer 1

`8/(y+2)=16/11`

Explanation:

`"given "8/11=4/(y+2)`

`rArr8(y+2)=44larrcolor(blue)"cross-multiplying"`

`"divide both sides by 8"`

`(cancel(8)(y+2))/cancel(8)=44/8`

`rArry+2=44/8`

`rArr8/(y+2)=8/(44/8)=8xx8/44=64/44=16/11`

Answer 2

`y=7/2`

Explanation:

Solve:

`8/11=4/(y+2)`

Cross multiply the denominators by the opposite numerators.

`8(y+2)=4xx11`

Simplify.

`8(y+2)=44`

Expand.

`8y+16=44`

Subtract `16` from both sides.

`8y=44-16`

Simplify.

`8y=28`

Divide both sides by `8`.

`y=28/8`

Reduce by dividing the numerator and denominator by `4`.

`y=7/2`

Check the answer.

`8/11=4/(7/2+2)`

`0.72bar(72)=0.72bar(72)` Check!