At #"STP"# what is the molar quantity of dinitrogen gas which has a volume of #5.6*L#?

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Answer 1 · 2017-10-27T15:29:48

Well, at #"STP"#, the molar volume of an ideal gas is #22.4*L#...

And the definitions of #"STP"# seems to vary across curricula; there are a few different standards, of which you have to be mindul....

And so to get the molar quantity of dinitrogen, we take the quotient....

#"volume of gas"/"molar volume"=(5.6*L)/(22.4*L*mol^-1)=0.250*mol#...how many moles of #"nitrogen atoms"# in this molar quantity?

Answer 2 · 2017-10-27T15:35:43

# 0.249mols#

At STP, #22.414l# of #N_2# contain moles #= 1#mole

#5.6L# of #N_2# will contain moles #=# #(1mol)/"22.414liters"# #xx# #5.6liters#

# = 0.249mols#

Hope it helps...