What masses are associated with ... $a.$ a $1.5"mole"$ quantity of potassium; $b.$ a $2.5"mole"$ quantity of carbon; $c.$ a $1.5"mole"$ quantity of potassium; and $d.$ a $12.5"mole"$ quantity of helium?

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Answer 1 · 2017-10-28T08:30:35

For each question, we multiply the molar quantity by the molar mass to get an answer in grams as required....

$a.$ $1.50*molxx39.10*g*mol^-1=58.7*g*"potassium"$ .

$b.$ $2.50*molxx12.01*g*mol^-1=30.0*g*"carbon"$ .

$c.$ $0.250*molxx106.42*g*mol^-1=26.6*g*"palladium"$ .

$d.$ $12.5*molxx4.00*g*mol^-1=50.0*g*"helium"$ .

In each case the product, gives an answer with dimensions of mass...i.e. $cancel(mol)xxg*cancel(mol^-1)=g$ ...as is absolutely required....

From where did I get the individual atomic masses? Did I know them from memory?

What masses are associated with ... a.a. a 1.5*"mole"1.5*"mole" quantity of potassium; b.b. a 2.5*"mole"2.5*"mole" quantity of carbon; c.c. a 1.5*"mole"1.5*"mole" quantity of potassium; and d.d. a 12.5*"mole"12.5*"mole" quantity of helium?