What mass of water results from the combustion of #5.80*mg# of methane?

1 Answer
anor277
Oct 28, 2017

Approx. #13*mg# of water.......

Explanation:

We need a stoichiometric equation....

#CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(l)#...which tells us UNEQUIVOCALLY that the combustion of 1 mole of methane gives 2 moles of water.....

#"Moles of methane"=(5.80xx10^-3*g)/(16.04*g*mol^-1)=3.62xx10^-4*mol#

And the mass of water that results from combustion of this molar quantity is given by.....

#2xx3.62xx10^-4*molxx18.01*g*mol^-1=??*g#

Why did I multiply by #2#?

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