Question #b1734

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Answer 1 · 2017-10-29T10:12:15

#a = 1#
# b = 0#

Via factor theorem

let # f(x) = ax+b #

Factor theorem: #f(-a) = Rem(f(x)/(x+a))#
Where #Rem(x)# = Remainder of #x#

Hence #f(2) = 2#
and #f(-2) = -2#

Hence #2a+b = 2#
and # 2a-b# = 2

Solving simultaneously;
#4a = 4#
# a = 1 #
Rearanging;
# b = 2a - 2 #
# b = 0#

Hence;
#a = 1#
# b = 0#