Question #baf29

1 Answer
Daniel W.
Oct 29, 2017

Option 5 is the answer.

Explanation:

Algebra is your friend.

Lets take initial distance to be d and time to be t.
So initially the speed (v₁) is:
#v_1 = d/t#

Then distance is halved and time is doubled. So the distance is now #d/2# and time is #2t#. What is our expression for speed (v₂)?
#v_2 = (d//2)/(2t) = d/(4t) = ¼d/t#

Compare v₁ and v₂ :
#v_2 = v_1/4#

So the answer is option 5.

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