Question #42208

1 Answer
Nov 5, 2017

Answer:

#"619 g"#

Explanation:

The idea here is that we use the percent concentration by mass to show the number of grams of solute present for every #"100 g"# of a given solution.

In this case, you have a solution that is #2.23 color(blue)(%)# by mass silver nitrate, #"AgNO"_3#, so you can say that this solution will contain #"2.23 g"# of silver nitrate, the solute, for every #color(blue)("100 g")# of the solution.

#2.23 color(blue)(%)color(white)(.)"AgNO"_3 " "implies" " "2.23 g AgNO"_3 color(white)(.)"per"color(white)(.)color(blue)("100 g")color(white)(.)"of solution"#

So all you have to do here is to use the percent concentration of the solution as a conversion factor to find the mass of this solution that would contain #"13.8 g"# of solute.

#13.8 color(red)(cancel(color(black)("g AgNO"_3))) * "100 g solution"/(2.23 color(red)(cancel(color(black)("g AgNO"_3)))) = color(darkgreen)(ul(color(black)("619 g solution")))#

The answer is rounded to three sig figs.