Question

A man and woman are heterozygous for eye color, where blue eye color is homozygous recessive. What is the probability that two children in a row will have blue eyes?

Answer 1

`0.0625`

Explanation:

The Punnet square below shows the probabilities for eye color in the offspring of two heterozygous (Bb) parents.

If both parents are heterozygous for eye color, the probability that a child will have blue eyes is `1/4` or `0.25`, for each child, because each birth is an independent event.

However, the probability that two independent events will occur two times in a row, is determined by multiplying the probabilities of each independent event. So to determine the probability of having two children with blue eyes in a row, multiply the probability of each independent event.

`0.25xx0.25=0.0625`