A man and woman are heterozygous for eye color, where blue eye color is homozygous recessive. What is the probability that two children in a row will have blue eyes?

1 Answer
Nov 3, 2017

#0.0625#

Explanation:

The Punnet square below shows the probabilities for eye color in the offspring of two heterozygous (Bb) parents.

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If both parents are heterozygous for eye color, the probability that a child will have blue eyes is #1/4# or #0.25#, for each child, because each birth is an independent event.

However, the probability that two independent events will occur two times in a row, is determined by multiplying the probabilities of each independent event. So to determine the probability of having two children with blue eyes in a row, multiply the probability of each independent event.

#0.25xx0.25=0.0625#