Question #d00f2

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Answer 1 · 2017-12-08T10:20:02

#tanx-√3cotx+1=√3#

#=>tanx-sqrt3/tanx+1=sqrt3#

#=>tan^2x-sqrt3+tanx=sqrt3tanx#

#=>tan^2x+tanx-sqrt3tanx-sqrt3=0#

#=>tanx(tanx+1)-sqrt3(tanx+1)=0#

#=>(tanx+1)(tanx-sqrt3)=0#

When
#tanx+1=0#
#=>tanx=-1=tan(-pi/4)#

#=>x=npi-pi/4" where " n in ZZ#

when

#tanx-sqrt3=0#

#=>tanx=sqrt3=tan(pi/3)#

#=>x=kpi+pi/3" where " k in ZZ#