Question #cd2ef

1 Answer
Connie
Nov 3, 2017

Which variable are you solving for?

Explanation:

Solving for #z#:

#(2z)/2 =(4xy)/2#

#z = 2xy#.

Solving for #x#:

#(2z)/(4y) = (4xy)/(4y)#

#z/(2y) = x#, or

#x = z/(2y)#.

Solving for #y#:

#(2z)/(4x) = (4xy)/(4x)#

#z/(2x) = y#, or

#y = z/(2x)#.

Is this what you need, or is there another part to the problem?

Connie

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