Question

Question #cd9fe

Answer 1

The molecular formula is `C_12H_10O_2`.

Explanation:

In this question, we have given a compound with molecular formula `C_(6x)H_(5x)O_x`. It can also be written as:

`xC_(6)H_(5)O`

where x is an empirical unit and `C_(6)H_(5)O` is an empirical formula.

Here, we can use an empirical unit formula to find the value of x.

`x=frac("molecular mass")("empirical mass")`

The empirical mass of `C_(6)H_(5)O` is given by:

`=6x12.01 "g/mol"+ 5x1.008 "g/mol"+ 1x16"g/mol" = 93.1 "g/mol"`

Now,

`x=frac("186 g/mol")("93.1 g/mol") = 1.997 \approx 2`

Therefore the molecular formula is: `C_(12)H_(10)O_2`.