# Question ccb93

Jan 17, 2018

$42$ m

#### Explanation:

The initial data presents this like a conservation of momentum problem, but that's all dealt with already. Really, this is just a kinematics problem.

The forces on the airplane mess is constant, so the acceleration is constant. Therefore, we can use familiar equations:

$v = a t + {v}_{0}$
and
$\Delta x = \frac{1}{2} a {t}^{2} + {v}_{0} t$

From the first, we get $a$:
v = 0 = a t + v_0 = a * (8.4 s) + (10 m/s)#
$a = \frac{- 10 \frac{m}{s}}{8.4 s} = - 1.19 \frac{m}{s} ^ 2$
Therefore, using the second equation
$\Delta x = \frac{1}{2} \left(- 1.19 \frac{m}{s} ^ 2\right) {\left(8.4 s\right)}^{2} + \left(10 \frac{m}{s}\right) \cdot \left(8.4 s\right) = 42.0 m$