Question #02807

1 Answer
Nov 5, 2017

3.55 L

Explanation:

The molar mass of MnO_2 is 86.94 g/mol.

Calculating the number of moles of Cl_2,

"moles Cl"_2 = "12.0 g MnO"_2 (("1 mol MnO"_2) / ("86.94 g MnO"_2)) (("1 mol Cl"_2) / ("1 mol MnO"_2))

"moles Cl"_2 = "0.1380 mol"

Assuming that the gas is ideal,

PV = nRT

V = (nRT) / P

V = ((0.1380 mol) (0.082056 (L atm)/(mol K))(25 + 273.15)K)/(0.950atm)

V = "3.55 L"