Question

Question #f1525

Answer 1

`(2a)/(a-4a^2+1)`

Explanation:

Plug in `(4/(1-4a))` for `x`

`(4a(4/(1-4a)))/(4a+(4/(1-4a))) =((8a)/(1-4a))/((4a(1-4a)+4)/(1-4a))=((8a)/(1-4a))/((4a-16a^2+4)/(1-4a))`

Multiply numerator and denominator by `(1-4a)`

`((8a)/(1-4a))/((4a-16a^2+4)/(1-4a))= (8a)/(4a-16a^2+4)`

Factor denominator:

`(8a)/(4(a-4a^2+1))=(2a)/(a-4a^2+1)`