What is the range of possible values of internal angles of a regular #n#-sided polygon?

1 Answer
Feb 25, 2018

Essentially #[pi/3, pi)#, but only takes certain discrete values...

Explanation:

What is the range of possible values of internal angles of a regular #n#-sided polygon?

The sum of internal angles of a triangle is #pi# radians (#180^@#).

An #n#-sided polygon can be dissected into #n-2# triangles with vertices at the vertices of the polygon.

Hence each internal angle of a regular #n#-sided polygon is:

#(n-2)/n pi = (1-2/n)pi" "# radians

Note that #n >= 3#, and hence each internal angle is in the range:

#[pi/3, pi)#

The actual possible values are:

#pi/3, pi/2, (3pi)/5, (2pi)/3, (5pi)/7, (3pi)/4, (7pi)/9, (4pi)/5,...#