How do you graph the equation #x - 3y = 3#?

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Answer 1 · 2017-11-06T18:02:04

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#0 - 3y = 3#

#-3y = 3#

#(-3y)/color(red)(-3) = 3/color(red)(-3)#

#y = -1# or #(0, -1)#

Second Point: For #x = 3#

#3 - 3y = 3#

#3 - color(red)(3) - 3y = 3 - color(red)(3)#

#0 - 3y = 0#

#-3y = 0#

#(-3y)/color(red)(-3) = 0/color(red)(-3)#

#y = 0# or #(3, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.025)((x-3)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x-3y-3)(x^2+(y+1)^2-0.025)((x-3)^2+y^2-0.025)=0 [-10, 10, -5, 5]}