How do you graph the equation $x - 3 y = 3$ $x - 3y = 3$ ?

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Answer 1 · 2017-11-06T18:02:04

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$0 - 3 y = 3$ $0 - 3y = 3$

$- 3 y = 3$ $-3y = 3$

$\frac{- 3 y}{- 3} = \frac{3}{- 3}$ $(-3y)/color(red)(-3) = 3/color(red)(-3)$

$y = - 1$ $y = -1$ or $(0, - 1)$ $(0, -1)$

Second Point: For $x = 3$ $x = 3$

$3 - 3 y = 3$ $3 - 3y = 3$

$3 - 3 - 3 y = 3 - 3$ $3 - color(red)(3) - 3y = 3 - color(red)(3)$

$0 - 3 y = 0$ $0 - 3y = 0$

$- 3 y = 0$ $-3y = 0$

$\frac{- 3 y}{- 3} = \frac{0}{- 3}$ $(-3y)/color(red)(-3) = 0/color(red)(-3)$

$y = 0$ $y = 0$ or $(3, 0)$ $(3, 0)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.025)((x-3)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x-3y-3)(x^2+(y+1)^2-0.025)((x-3)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

How do you graph the equation x−3y=3x - 3y = 3?