Question #11715

1 Answer
Feb 26, 2018

From Kepler's Law we know, #T^2 prop r^3#

So, #T^2 = K r^3#(let, #K# is a constant)

Now,we know, #V=omega r = (2pi)/ T *r#

So, #T=(2pi)/V *r#

So, #4 pi^2 r^2 / V^2 = K r^3#

Now,multiplying both side by #m# and rearranging to write,

#(mV^2) / r^2 =1/K (4 pi^2m)/r^3#

Multiplying both side by #r#,we get,

#(mV^2)/r = ((4pi^2)/K)m/r^2= C m/r^2#

So, #(mV^2)/r# is the required centripetal force for a planet to move round the Sun i,e the attractive force or the gravitational force acting in between the planet of mass #m# and radius of orbit #r#

So, we can write, #F= C m/r^2# (where, #C# is a constant)

This is the Newton's Law of gravitation.

In reality #C= GM# (where, #G# is the gravitational constant and #M# is the mass of sun)