# Question #9a085

Nov 10, 2017

The same....

#### Explanation:

Mass = defined as the amount of matter. If you tranport it to the Moon the amount of matter won't change so the Mass stays the same.
The WEIGHT is an entirely different matter (no pun intended)
Weight is a force, calculated as $F = m \cdot a$
Here on earth $a$ (the acceleration, caused by the gravitational "pull" of the Earth) is roughly 9.8 $m$ /${s}^{2}$., let's round up to 10$m$ /${s}^{2}$.

The weight (Force) therefore is $37 k g \cdot 10 m$ /${s}^{2}$ = $370 K g m$/${s}^{2}$, or 370 N (Newton).

In deep space there is no noticeable influence of gravitational fields (for our purposes in this answer at least) so the weight will be $37 k g \cdot 0 m$ /${s}^{2}$ = $0 K g m$/${s}^{2}$, or $0 N$, in other words: weightless.

The gravitational pull on the surface of the Moon is roughly 1/6th , so the weight of the object would be about 62 N..