# Question #1e971

##### 2 Answers

In simple terms, and for lack of a better description, let's say it depends on the amount of "active groups"

#### Explanation:

Let's take NaOH: this readily (and completely) disintegrates in water, and produces

If you have 1 Mol of NaOH and dissolve it in 1 litre of

Now consider the same with 1 Mol

This will dissolve into

**BUT:**

You now have twice as many

Also, we are dealing here with **2**

Therefore, though you started with 1 Mol of

Could be a bit confusing, that's why Normality was introduced:

So:

a solution of 1 M

a solution of 1 M

Same of course goes for acids, where you take

#### Explanation:

For example, if you have 1 M sulphuric acid, in an acid/base reaction it would be 2 N ("twice normal"), due to each mole of sulphuric acid yielding 2 moles of

On the other hand, if you used 1 M sulphuric acid for something like precipitation of sulphates, then it would be 1 N ("normal") because each mole of sulphuric acid yields a mole of sulphate ions.