Question

A molar quantity of gas at a pressure of `1*atm`, expresses a volume of `44.8*L`. What is the temperature of the gas under question?

Answer 1

Well for a given molar quantity, the volume occupied by a gas.....

Explanation:

...is a state function of pressure and temperature.....and most commonly the function we use is the ideal gas equation.....

`PV=nRT`, with `"P = pressure"`, `"V = volume"`, `n="moles of gas"`, `"T = absolute temperature"`, and `"R = a constant"`...

Chemists typically use `R=0.0821*L*atm*K^-1*mol^-1`.

And so here we ASSUME a molar quantity, a pressure of `1*atm`....and `"volume"=44.8*L`....and solve for `T`

`T=(PV)/(nR)=(1*atmxx44.8*L)/(1*molxx0.0821*(L*atm)/(K*mol))`

`=545.7*1/K^-1=545.7*1/(1/K)=545.7*K`