Question #2851d
1 Answer
Nov 14, 2017
See the answer below...
Explanation:
#cos2x=sqrt3/2#
#=>cos2x=cos (pi/6)#
#=>2x=pi/6#
#=>x=pi/12# [ANS]Hope it helps...
Thank you...
See the answer below...
#cos2x=sqrt3/2#
#=>cos2x=cos (pi/6)#
#=>2x=pi/6#
#=>x=pi/12# [ANS]Hope it helps...
Thank you...